Vector quantities have magnitude and direction.
Represented by an arrow
In 2D require two numbers to specify (e.g. azimuth and length, x and y coordinates)
In 3D require 3 numbers (eg plunge trend and length, x, y and z coordinates)
Sometimes it's useful to define vectors that have unit magnitude. E.g. plunge and trend measurements have direction but no magnitude. We arbitrarily treat them as vectors one unit long
Represented bold in text, in handwriting with line over top
If we have a coordinate system its convenient to represent vectors as three components by projecting onto three axes eg:
east
north
upx
y
zx1
x2
x3
If magnitude is F, and angles to x1, x2, x3 axes are θ1 θ2 θ3 then the magnitudes of the three components are
f1 = F cos θ1
f2 = F cos θ2
f3 = F cos θ3
Note that to get back to magnitude given 3 components we use F2 = f12+f22+f32
For geological measurements that have orientation but no magnitude, we use a magnitude of 1
The magnitudes of the three components are
cos θ1
cos θ2
cos θ3
Converting plunge and trend to direction cosines:
l = sin T cos P
m = cos T cos P
n = -sin P
Trend depends on how the inverse tan function is implemented. Most calculators give inverse tan between -90 and +90
T =Tan-1(m/l) if l is positive or
T =Tan-1(m/l) + 180 if l is negative
P =Sin-1(n)
The magnitude of vector a, represented as |a| or just a is given by |a|= √(ax2+ ay2+ az2)
Vectors are added by adding their components.
Alternatively the calculation can be carried out graphically using the well known parallelogram rule.
For two vectors a and b the dot product
a.b = abcosθ where a and b are the magnitudes of a and b and θ is the angle between the vectors.
For unit vectors â.b = cosθ
So, we can use the dot product to calculate the angle between two lines.
For two vectors a and b the cross product a x b = c is given by
The cross product is a third vector mutually perpendicular to the first two, where a, b and c form a right-handed set (i.e. they have the same relative arrangement as x, y and z). The magnitude of a x b is absinθ.
Hence we can use the cross product to find the line perpendicular to two other lines.
Caution: even if a and b are unit vectors, the magnitude of c is not equal to one, and therefore its components are not direction cosines. To convert them to direction cosines, divide each by the magnitude of c, represented as |c| or c = √(cx2+ cy2+ cz2)